From owner-freebsd-questions Sat Apr 3 0:30:11 1999 Delivered-To: freebsd-questions@freebsd.org Received: from ptldpop1.ptld.uswest.net (ptldpop1.ptld.uswest.net [198.36.160.1]) by hub.freebsd.org (Postfix) with SMTP id 251A914F98 for ; Sat, 3 Apr 1999 00:30:08 -0800 (PST) (envelope-from dpilgrim@uswest.net) Received: (qmail 10256 invoked by alias); 3 Apr 1999 02:56:52 -0000 Delivered-To: fixup-freebsd-questions@FreeBSD.ORG@fixme Received: (qmail 10206 invoked by uid 0); 3 Apr 1999 02:56:50 -0000 Received: from fdsl89.ptld.uswest.net (HELO uswest.net) (216.161.80.89) by ptldpop1.ptld.uswest.net with SMTP; 3 Apr 1999 02:56:50 -0000 Message-ID: <3705833D.4C8CDFC8@uswest.net> Date: Fri, 02 Apr 1999 18:55:57 -0800 From: Darren Pilgrim Organization: Neatly stacked heaps of digital chaos X-Mailer: Mozilla 4.51 [en] (Win98; U) X-Accept-Language: en MIME-Version: 1.0 To: Jamie Lawrence Cc: freebsd-questions@FreeBSD.ORG Subject: Re: Drive geometry for IBM Ultrastar References: <4.1.19990402171611.00cfac20@mail.thirdage.com> Content-Type: text/plain; charset=us-ascii Content-Transfer-Encoding: 7bit Sender: owner-freebsd-questions@FreeBSD.ORG Precedence: bulk X-Loop: FreeBSD.ORG Jamie Lawrence wrote: > This isn't strictly on charter, so I hope people don't mind. > > I bought 2 IBM drives, one the DRVS-18V and the other the DRVS-9V, > 18 and 9 gig 10,000 RPM drives. They didn't come with geometry info, > and I can't find it anywhere. I can find that there are 7065 cylinders, > and 10 platters, 20 heads on the 18G disk, and 5/10 on the 9. The > sector size is configurable, 512-732 bytes. > > What I can't find it the number of tracks, or how many sectors per > track (assuming, say, 512 byte sectors). > > Does anyone know a way to derive this information? Or does anyone > have these drives and know? I broke down and called IBM tech support, > and they don't seem to know either, and just promised a call back which > never came. Tracks is another word for cylinders. There's a simple math formula you can use: cylinders * heads * sectors/track * sector size = capacity Since you know four of the five, you can solve for the unknown by rearranging the formula: capacity / (cyls * heads * sector size) = sectors/track Remember to use commercial GB (10^9) instead of true GB (1024^3). I'm wondering why you need to figure out this information, your SCSI HBA is supposed to figure it all out for you. -- dpilgrim@uswest.net /\ / __ Our lies are merely the gryph@mindless.com / \/OC/URNE truth of another world ICQ: 29880099 Death is not a kill -9, just a DALnet: anim0s make world and shutdown -r now PGPKey available To Unsubscribe: send mail to majordomo@FreeBSD.org with "unsubscribe freebsd-questions" in the body of the message