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From: "Brandon Hinesley" <brandonh@hotandcold.biz>
To: "'Giorgos Keramidas'" <keramida@ceid.upatras.gr>
Date: Thu, 3 Nov 2005 16:33:34 -0800
Organization: Advanced Mechanical Systems, Inc.
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Cc: freebsd-questions@freebsd.org
Subject: RE: Cron Job will not run.
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Okay, the problem seems to be with a certain part of my script.  Like I
said, it works fine when I start it manually (./)

I set up a few "checkpoints" if you will, and I determined that it's this
loop that cron has a problem with:

for (( i = $numbkups ; i >= 2 ; i-- ))
do
    let from=i-1
    mv -fv $dbkups/$from $dbkups/$i
done

This loop never runs and neither does anything after it.  I don't see why
cron would have any problem with this, or why this would exit the script...