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Date: Tue, 06 May 2003 15:00:58 -0300
From: "Daniel C. Sobral" <dcs@tcoip.com.br>
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To: "Jacques A. Vidrine" <nectar@freebsd.org>
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cc: "Andrey A. Chernov" <ache@nagual.pp.ru>
cc: Daniel Eischen <eischen@pcnet1.pcnet.com>
cc: freebsd-arch@freebsd.org
Subject: Re: `Hiding' libc symbols
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Jacques A. Vidrine wrote:
> On Tue, May 06, 2003 at 09:56:06AM +0200, Harti Brandt wrote:
>=20
>>There is no guarantee that you 'fix' the port by hiding the symbol.  Yo=
u
>>may as well break it. This depends on the function itself and on the
>>internal relationships in libc. You have to go through each individual
>>port and see what happens anyway.
>=20
>=20
> Please explain.  I _am_ guaranteed that keeping the port from hijacking=

> strlcpy calls in libc will not break the port.  How could the port rely=

> on the internals of libc?

Well... if I instrument all memory allocating functions (by providing my =

own copies) and I call a function that allocates memory by itself and=20
expects my application to free that memory at some point, I expect the=20
kernel to use one of my functions to do it.

--=20
Daniel C. Sobral
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