From owner-freebsd-questions  Thu Jan 17  9:52: 5 2002
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Date: Thu, 17 Jan 2002 09:52:01 -0800 (PST)
From: ann kok <annkok2001@yahoo.com>
Subject: Re: command ls question
To: smorton@acm.org
Cc: freebsd-questions@FreeBSD.ORG
In-Reply-To: <3C46F7E5.7050906@verizon.net>
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Dear all

My english is not good
so it makes you confusion

From the book, it shows rm temp?
it can remove tempa tempb temp1

? stands for one char

If I have files a, bc , ef, but ls ? doesn't work!


--- Simon Morton <simon.morton@verizon.net> wrote:
> ann kok wrote:
> 
> > Dear all
> > 
> > I would like to know how about command ls
> > 
> > display a char #ls ? doesn't work
> 
> 
> Works for me...
> 
> holly:~> ls ?
> ls: No match.
> holly:~> echo "foo" > f
> holly:~> ls ?
> f
> holly:~>
> 
> 
> > remove the files temp1 temp2 temp3
> > 
> > #rm temp [1-5 7-9] doesn't work
> 
> 
> It works if you remove the spaces.
> 
> holly:~> echo "foo" > temp1
> holly:~> echo "foo" > temp2
> holly:~> echo "foo" > temp3
> holly:~> rm temp[1-57-9]
> holly:~> ls temp*
> ls: No match.
> holly:~>
> 
> 
> > 
> > and
> > 
> > ls doesn't accurate to display disk space
> > because some files are link by command ln
> > it counts double
> 
>  >
> 
> > is it right?
> 
> 
> True.  Use du or df to find out about disk space.
> 
> -- 
> http://www.SimonMorton.com
> smorton at acm dot org
> \rm -rf /bin/laden
> 


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