From owner-freebsd-hackers Wed Oct 25 14:39:14 1995 Return-Path: owner-hackers Received: (from root@localhost) by freefall.freebsd.org (8.6.12/8.6.6) id OAA19258 for hackers-outgoing; Wed, 25 Oct 1995 14:39:14 -0700 Received: from cwbone.bsi.com.br ([200.250.250.14]) by freefall.freebsd.org (8.6.12/8.6.6) with ESMTP id OAA19220 for ; Wed, 25 Oct 1995 14:38:56 -0700 Received: (from lenzi@localhost) by cwbone.bsi.com.br (8.6.11/8.6.9) id TAA03767; Wed, 25 Oct 1995 19:49:27 GMT Date: Wed, 25 Oct 1995 19:49:26 +0000 () From: Sergio Lenzi To: hackers@freebsd.org Subject: Re: more boot disk.... In-Reply-To: <199510252120.OAA19573@phaeton.artisoft.com> Message-ID: MIME-Version: 1.0 Content-Type: TEXT/PLAIN; charset=US-ASCII Sender: owner-hackers@freebsd.org Precedence: bulk On Wed, 25 Oct 1995, Terry Lambert wrote: > > It can't. You can't guarantee to be able to read data (like /kernel) > from an 'a' slice that ends after the 1023'rd cylinder because you > can only stuff a 10 bit value into the INT 21/13 calls. > > Since the boot code on DOS systems is BIOS based, you are screwed. > Ok but... If I make a FreeBSD slice that begins on cyl 1 for example, and in that slice I make some filesystems this way: rootfs 60Mb starting on cyl 1 swap 100MB usr 500MB home 700MB I supose that the rootf ,where the kernel resides, is in the beggining of the disk, so accessible by the bios right???? So if I partition the disk this way the system will work. Thanks any oppinion... Lenzi.