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Date: Fri, 9 May 2014 16:45:46 +0200
From: Polytropon <freebsd@edvax.de>
To: "Ivailo A. Tanusheff" <ITanusheff@postbank.bg>
Subject: Re: Bourne variable unset outside while()
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Cc: Rick Miller <vmiller@hostileadmin.com>,
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On Fri, 9 May 2014 06:42:45 +0000, Ivailo A. Tanusheff wrote:
> Hi,
> 
> I think you can check out this:
> http://stackoverflow.com/questions/7482510/variable-incrementing-in-bash
> 
> So I sugest you do the same trick or use different approach - awk or something like this.

This actually works (and is a good idea to get rid of my suggested
`awk ...` call per each line of input). In "here documents", variable
expansion can be used. If the input will be coming from a file
instead, using < /the/file can be done.

	#!/bin/sh

	fs="freebsd-ufs gprootfs 1G
	freebsd-swap gpswapfs 1G
	freebsd-ufs gpvarfs 1G"

	while read -r fstype fslabel fssize; do
	        labels="${labels} ${fslabel}"
	done << EOF
	"${fs}"
	EOF

	echo "labels = ${labels}"

The result is:

	labels =  gprootfs gpswapfs gpvarfs

There's a leading space because at the first addition, ${labels}
is empty, a space and the 1st entry are then added. The awk approach
didn't have that "bug", erm... feature. ;-)



-- 
Polytropon
Magdeburg, Germany
Happy FreeBSD user since 4.0
Andra moi ennepe, Mousa, ...