Date: Sun, 11 Jan 2009 21:07:17 -0600 From: Dan Nelson <dnelson@allantgroup.com> To: Jeffrey Goldberg <jeffrey@goldmark.org> Cc: "mail.list freebsd-questions" <freebsd-questions@freebsd.org> Subject: Re: bash versus sh test builtin Message-ID: <20090112030717.GA57874@dan.emsphone.com> In-Reply-To: <7740275E-77AA-45C1-B95E-C1F62D2AAB29@goldmark.org> References: <7740275E-77AA-45C1-B95E-C1F62D2AAB29@goldmark.org>
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In the last episode (Jan 11), Jeffrey Goldberg said: > The -ne operator for [ in /bin/sh doesn't seem to work as in bash. > Also the bash behavior here is what matches /bin/[ most closely. > > $ /bin/sh > $ if [ $UID -ne 0 ] ; then > > echo not root > > fi > [: -ne: unexpected operator > $ exit > $ echo $SHELL > /usr/local/bin/bash > [jeffrey@dobby ~/src/mount-rsnap]$ if [ $UID -ne 0 ] ; then > > echo not root > > fi > not root > > Does anyone have a recommendation of how to run this simple test in / > bin/sh and how to write tests reasonably portably? UID=$(id -u) if [ $UID -ne 0 ] ; then echo not root fi UID is not a variable set by /bin/sh, which is why the test fails. http://www.opengroup.org/onlinepubs/9699919799/utilities/V3_chap02.html#tag_18_05_03 -- Dan Nelson dnelson@allantgroup.com
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