Date: Thu, 22 Jan 2009 14:51:31 -0800 From: Nerius Landys <nlandys@gmail.com> To: Maxim Khitrov <mkhitrov@gmail.com> Cc: freebsd-questions@freebsd.org Subject: Re: shell scripting, how to auto-timeout? Message-ID: <560f92640901221451j2e2b259bw1559a8c8d8912941@mail.gmail.com> In-Reply-To: <26ddd1750901221333x5356f4f3l6b6410fc05d4e6d4@mail.gmail.com> References: <560f92640901221241y4fc1620aree083a812c1f3c8d@mail.gmail.com> <26ddd1750901221333x5356f4f3l6b6410fc05d4e6d4@mail.gmail.com>
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> #!/bin/sh
>
> java()
> {
> echo 'start'
> sleep 5
> echo 'stop'
> }
>
> sleep 1 && kill $$ &
> java
> kill $!
>> {
> echo 'start'
> sleep 5
> echo 'stop'
> }
>
> sleep 1 && kill $$ &
> java
> kill $!
That is very genious. However, I had to add an "exec" to the parent
script. Here is the test parent script, see the exec line below:
#!/bin/sh
cd `dirname "$0"`
THIS_SCRIPT_PROCESS="$$"
sleep 5 && echo "killing parent script, PID $THIS_SCRIPT_PROCESS" &&
kill "$THIS_SCRIPT_PROCESS" &
TERMINATOR_PROCESS="$!"
exec ./child_script
echo "killing terminator process, PID $TERMINATOR_PROCESS" && kill
"$TERMINATOR_PROCESS"
And here is the child script "child_script":
#!/bin/sh
echo "start"
while true; do
# Infinite loop; use some CPU so that it's easy to find this in the
output of top.
echo "foo" > /dev/null
done
echo "stop"
Without the "exec" in the parent script, the parent's child is not
killed when the parent is killed.
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