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Date: Sat, 8 Mar 2003 15:50:11 -0800 (PST)
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To: freebsd-bugs@FreeBSD.org
Cc: 
From: Robert Drehmel <robert@zoot.drehmel.com>
Subject: Re: bin/49038: /bin/sh does not undefine a function when unset is issued
Reply-To: Robert Drehmel <robert@zoot.drehmel.com>
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The following reply was made to PR bin/49038; it has been noted by GNATS.

From: Robert Drehmel <robert@zoot.drehmel.com>
To: freebsd-gnats-submit@FreeBSD.org
Cc: jau@iki.fi
Subject: Re: bin/49038: /bin/sh does not undefine a function when unset is issued
Date: Sun, 9 Mar 2003 00:49:45 +0100

 Hello.
 
 > The bourne shell does not undefine a previously declared shell
 > function when unset command is given though the manual pages
 > so imply.
 
 I think it is pretty clear that a plain "unset name" does not
 undefine functions.
 
 From the sh(1) manual page:
 
 """
 unset [-fv] name ...
 The specified variables or functions are unset and unexported.
 If the -v option is specified or no options are given, the name
 arguments are treated as variable names.  If the -f option is
 specified, the name arguments are treated as function names.
 """
 
 > This is a serious portability problem for imported shell scripts.
 
 If these shell scripts rely on "unset name" to remove a function
 named "name", they should be regarded as unportable.
 
 From POSIX.1-2001:
 
 """
 If neither -f nor -v is specified, name refers to a variable; if a
 variable by that name does not exist, it is unspecified whether a
 function by that name, if any, shall be unset.
 """
 
 ciao,
 -robert

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