Date: Fri, 13 Dec 2002 17:09:42 +0200 From: Ruslan Ermilov <ru@FreeBSD.ORG> To: "Andrey A. Chernov" <ache@nagual.pp.ru> Cc: bwk@bell-labs.com, obrien@FreeBSD.ORG, current@FreeBSD.ORG Subject: Re: New AWK bug with collating Message-ID: <20021213150942.GE86638@sunbay.com> In-Reply-To: <20021213134106.GA32832@nagual.pp.ru> References: <20021213122654.GA32014@nagual.pp.ru> <20021213123240.GC86638@sunbay.com> <20021213134106.GA32832@nagual.pp.ru>
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On Fri, Dec 13, 2002 at 04:41:06PM +0300, Andrey A. Chernov wrote:
> On Fri, Dec 13, 2002 at 14:32:40 +0200, Ruslan Ermilov wrote:
> > Pardon my ignorance here, but the following fragment
> > returns -1, doesn't it?
> >=20
> > #include <stdio.h>
> > void
> > main(void)
> > {
> > int i;
> >=20
> > i =3D (unsigned char)1 - (unsigned char)2;
> > printf("%d\n", i);
> > }
>=20
> It very depends on compiler, i.e. does it implements "value preseving" or=
=20
> "unsigned preserving" for 'char' type conversions. Or ANSI C vs. common C=
=20
> mode. Better be safe for both.
>=20
> Read 6.10.1.1 section here:
> http://wwwrsphysse.anu.edu.au/doc/DUhelp/AQTLTBTE/DOCU_067.HTM
>=20
This is handled by the -traditional flag of gcc(1):
: `-traditional'
:=20
: Attempt to support some aspects of traditional C compilers.
: Specifically:
:=20
[...]
:=20
: * Integer types `unsigned short' and `unsigned char' promote to
: `unsigned int'.
With -traditional, the code I quoted still produces -1.
In any case, this section doesn't apply to this case because
no conversion described in section 6.10 is ever done here,
since both operands are of the same type, "unsigned char".
Cheers,
--=20
Ruslan Ermilov Sysadmin and DBA,
ru@sunbay.com Sunbay Software AG,
ru@FreeBSD.org FreeBSD committer,
+380.652.512.251 Simferopol, Ukraine
http://www.FreeBSD.org The Power To Serve
http://www.oracle.com Enabling The Information Age
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