Date: Sun, 24 Feb 2008 21:00:34 +0200 From: "Jaco le Roux" <jaco@videoafrica.co.za> To: <freebsd-questions@freebsd.org> Subject: RE: DHCP Server Message-ID: <000101c87717$9044a4b0$b0cdee10$@co.za> In-Reply-To: <20080224195523.V4625@wojtek.tensor.gdynia.pl> References: <000001c87710$83243770$896ca650$@co.za> <20080224195523.V4625@wojtek.tensor.gdynia.pl>
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> -----Original Message-----
> From: Wojciech Puchar [mailto:wojtek@wojtek.tensor.gdynia.pl]
> Sent: 24 February 2008 08:56 PM
> To: Jaco le Roux
> Cc: freebsd-questions@freebsd.org
> Subject: Re: DHCP Server
>
> > BSD box, the other client is connected via a bridge on the first client.
I
> > have a section in my /usr/local/etc/dhcpd.conf to assign a specific IP
to
> > client #1:
> >
> > host myhost {
> > hardware ethernet xx:xx:xx:xx:xx:xx;
> > fixed address 192.168.1.16;
> > }
> >
> > The problem is, both client #1 and #2 get assigned the same IP address
which
> > results in a conflict (I'm guessing because they appear to be behind the
>
> it means that the first client's "bridge" is not a bridge.
Hm. Well it's a bridge made by windows xp from one interface to another.
You're telling me that it won't work like that?
If I use 'arp ip-address' on the two clients, it resolves to the same MAC
address :/
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