Date: Wed, 15 Aug 2012 10:33:46 +0200 From: Daniel Grech <dgre090@gmail.com> To: freebsd-hackers@freebsd.org Subject: Unsigned Integer Encoding Message-ID: <CAG167sY3-i_MimZGJ7qv9NC-u6e2w6RWq_fZt3amFn3%2BjdeKbQ@mail.gmail.com>
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Hi,
I have what is probably a really elementary question but I can't seem to
figure it out. In the following snippet of code, why is it that a and b do
not have the same value in the end ? :
#define uint32_t unsigned int
#define uint16_t unsigned short
#define uint8_t unsigned char
#define uint64_t unsigned long long
int main ()
{
uint32_t a = 0x01020304;
/* This prints 01020304 */
printf ("a = %0X \n",a);
uint32_t * b;
uint8_t bytes [] = {0x01,0x02,0x03,0x04};
b = (uint32_t *) bytes;
/* This prints 04030201 */
printf ("b= %0X \n", *b);
return 1;
}
Im asking this as I am currently encoding a protocol in which i receive
data as a sequence of bytes. Casting for example 4 bytes from this stream
leaves me with the situation in variable b, while the situation I am
looking to accomplish is the one in A (i.e. the bytes are not encoded in
reverse form).
Thanks in advance for your help.
Regards,
Daniel
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