Date: Tue, 25 Sep 2001 11:54:47 -0500 From: Dan Nelson <dnelson@allantgroup.com> To: Bill Schoolcraft <bill@wiliweld.com> Cc: freebsd-questions@FreeBSD.ORG Subject: Re: Shell argument limits at $9 ?? Message-ID: <20010925115446.A28233@dan.emsphone.com> In-Reply-To: <Pine.GSO.4.33.0109250836490.18238-100000@corten8.billschoolcraft.com> References: <Pine.GSO.4.33.0109250836490.18238-100000@corten8.billschoolcraft.com>
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In the last episode (Sep 25), Bill Schoolcraft said: > In a script I'm working on called "testit" it calls for echoing the > arguments entered. This issue seems to reveal itself as follows when > I execute the following. > > testit a b c d e f g h i j k l m > > and then I go to echo $9 and it shows "i" but when I echo $10 it > shows "a0" and $11 shows "a1" apparently in hex. No; it's simply taking the first digit as the variable name, printing its contents, then continuing on with the letter "0" (or "1"). This is by design; if you need to access past the 9th argument, use brace syntax: ${10} -- Dan Nelson dnelson@allantgroup.com To Unsubscribe: send mail to majordomo@FreeBSD.org with "unsubscribe freebsd-questions" in the body of the message
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