Date: Thu, 22 Dec 2005 14:14:09 -0500 From: Mikhail Teterin <mi+mx@aldan.algebra.com> To: Dan Nelson <dnelson@allantgroup.com> Cc: freebsd-questions@freebsd.org Subject: Re: what's an equivalent for the following Perl one-liner? Message-ID: <200512221414.10321.mi%2Bmx@aldan.algebra.com> In-Reply-To: <20051222183250.GB39217@dan.emsphone.com> References: <200512211704.49530.mi%2Bmx@aldan.algebra.com> <20051222183250.GB39217@dan.emsphone.com>
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четвер 22 грудень 2005 13:32, Dan Nelson Ви написали: > In the last episode (Dec 21), Mikhail Teterin said: > > I'd like a sed string, that will remove both the carriage returns and > > the blanks at eol in one go. Perl appears to recognize the \r > > character and DTRT: > > > > perl -p -e 's,[ \r]+$,,' < in > out > > > > What's the sed's equivalent? Thanks! > > sed -E 's,[ ^M]*$,,' < in > out > > Note the ^M is a single control-character (entered via Ctrl-V Ctrl-M at > a shell prompt for example). Yes, I used this in the past, but the ports' Makefiles are supposed to be ASCII-only :-( > sed does not parse backslash-escapes except for \n which represents a > newline. Is not that a bug really? There may be some legacy reasons not to do it by default, but I'd expect the -E flag to turn on the recognition of such symbols... Thanks! -mi
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