Date: Sat, 15 Mar 2008 19:49:22 -0500 From: "Paul A. Procacci" <pprocacci@datapipe.com> To: Modulok <modulok@gmail.com> Cc: freebsd-questions@freebsd.org Subject: Re: Can one list permission bits numerically... Message-ID: <47DC6E92.1000300@datapipe.com> In-Reply-To: <64c038660803151511r6ae6d229v484769cfe38043bc@mail.gmail.com> References: <64c038660803151511r6ae6d229v484769cfe38043bc@mail.gmail.com>
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Modulok wrote: > Perhaps I missed it somewhere in the man page, but is there a way to > list files with their permission bits displayed as numeric (octal, as > in chmod(1)), instead of symbolic? Something like: > > ls -lF -imaginaryFlag > > 0755 4 Modulok Modulok 512 Dec 17 18:39 dir1/ > 0644 1 Modulok Modulok 101786 Feb 23 05:53 file1 > 0644 1 Modulok Modulok 140097 Feb 13 23:38 file2 > .... > > Thanks. > -Modulok- > _______________________________________________ > freebsd-questions@freebsd.org mailing list > http://lists.freebsd.org/mailman/listinfo/freebsd-questions > To unsubscribe, send any mail to "freebsd-questions-unsubscribe@freebsd.org" > Maybe something like this will suit you: stat -f "%p %l %u %g %z %m %N" * It produces output similar to the following: 100755 1 0 0 64 1201845218 blah The fields that I choose are in the man page, so it should be easy reading, and is pretty close to `ls -l`. As for as `ls` having this ability, it doesn't. Cheers.
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