Date: Sun, 21 Sep 2003 14:44:04 -0400 From: Adam McLaurin <blueeskimo@gmx.net> To: freebsd-questions@freebsd.org Subject: Extracting the label of a CD Message-ID: <1064169843.674.12.camel@jake>
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--=-vz7x8j/vKz9Ezdkz5g6d Content-Type: text/plain Content-Transfer-Encoding: quoted-printable Is there any elegant way to extract the label of a CD in FreeBSD 5.x ? I can use dd to get to it, but it's far from elegant. Wondering if there is some ioctl to do it cleanly; maybe even something in ports. If anyone is curious, this is how I'm doing it now: -$ dd if=3D/dev/acd0a bs=3D64k |strings -a |head -n 3 |tail -n 1 =20 I don't think it's safe to assume that it's always on the 3rd line, but that seems to be the case quite often. Thanks, --=20 Adam McLaurin <blueeskimo@gmx.net> --=-vz7x8j/vKz9Ezdkz5g6d Content-Type: application/pgp-signature; name=signature.asc Content-Description: This is a digitally signed message part -----BEGIN PGP SIGNATURE----- Version: GnuPG v1.2.3 (FreeBSD) iD8DBQA/bfFzt+DSc2Q4lGYRAjoEAJ9U7Djq8/g2uVpYRbQqZs534msitQCgx+K/ yHON7MioUU5IlSvWqtMQJ2Y= =ZChf -----END PGP SIGNATURE----- --=-vz7x8j/vKz9Ezdkz5g6d--
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