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Date: Sat, 30 Aug 2008 20:29:56 -0500
From: Paul Schmehl <pschmehl_lists@tx.rr.com>
To: "Ivan \"Rambius\" Ivanov" <rambiusparkisanius@gmail.com>,
	FreeBSD Questions <freebsd-questions@freebsd.org>
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Subject: Re: Formatting dates to a specific pattern
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--On August 31, 2008 2:52:07 AM +0300 "Ivan \"Rambius\" Ivanov"=20
<rambiusparkisanius@gmail.com> wrote:

> Hello,
>
> I need to format the current date (as returned by date(1) ) to the
> pattern m-d-yyyy, where m is the month in one or digits, d is the day
> in one or two digits, and yyyy is the year in four digits. The problem
> for me is the day and the month, for example August should be 8, and
> not 08, and 5th of September should be 9-5-2008 and not 09-05-2008. I
> read the man page of date(1) but date(1) seems to always put leading
> zeros.
>
> I appreciate any help on how to format the date the way I want.
>

# date "+%m-%d-%Y" | sed 's/^0//g'
8-30-2008

Paul Schmehl, If it isn't already
obvious, my opinions are my own
and not those of my employer.
******************************************
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