From owner-freebsd-questions@FreeBSD.ORG Sat Mar 21 14:10:43 2009 Return-Path: Delivered-To: freebsd-questions@freebsd.org Received: from mx1.freebsd.org (mx1.freebsd.org [IPv6:2001:4f8:fff6::34]) by hub.freebsd.org (Postfix) with ESMTP id D4D9A1065702 for ; Sat, 21 Mar 2009 14:10:43 +0000 (UTC) (envelope-from msoulier@digitaltorque.ca) Received: from mail.storm.ca (unknown [IPv6:2607:f0b0:0:6:209:87:239:66]) by mx1.freebsd.org (Postfix) with ESMTP id 8DA878FC08 for ; Sat, 21 Mar 2009 14:10:43 +0000 (UTC) (envelope-from msoulier@digitaltorque.ca) Received: from anton.digitaltorque.ca (hs-216-106-102-79.storm.ca [216.106.102.79]) by mail.storm.ca (8.14.2+Sun/8.14.2) with ESMTP id n2LCn6kk027753 for ; Sat, 21 Mar 2009 08:49:12 -0400 (EDT) Received: by anton.digitaltorque.ca (Postfix, from userid 1000) id 808618600CE; Sat, 21 Mar 2009 08:49:01 -0400 (EDT) Date: Sat, 21 Mar 2009 08:49:01 -0400 From: "Michael P. Soulier" To: freebsd-questions@freebsd.org Message-ID: <20090321124859.GA27682@anton.digitaltorque.ca> Mail-Followup-To: freebsd-questions@freebsd.org MIME-Version: 1.0 Content-Type: multipart/signed; micalg=pgp-sha1; protocol="application/pgp-signature"; boundary="6c2NcOVqGQ03X4Wi" Content-Disposition: inline User-Agent: Mutt/1.5.16 (2007-06-09) Subject: bash suddenly doesn't like $() syntax X-BeenThere: freebsd-questions@freebsd.org X-Mailman-Version: 2.1.5 Precedence: list List-Id: User questions List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , X-List-Received-Date: Sat, 21 Mar 2009 14:10:44 -0000 --6c2NcOVqGQ03X4Wi Content-Type: text/plain; charset=us-ascii Content-Disposition: inline Content-Transfer-Encoding: quoted-printable Hello, I'm running the shells/bash port on 6.3, and I recently ran a portupgrade. = All of a sudden when I login, my standard .profile and .bashrc are causing a bu= nch of error messages, like so -bash: command substitution: line 39: syntax error near unexpected token `)' -bash: command substitution: line 39: ` }")' It would see that bash no longer likes the $() command substitution syntax. Does that mean that it's defaulting to some sort of posix compatibility mode now?=20 Thanks, Mike --=20 Michael P. Soulier "Any intelligent fool can make things bigger and more complex... It takes a touch of genius - and a lot of courage to move in the opposite direction." --Albert Einstein --6c2NcOVqGQ03X4Wi Content-Type: application/pgp-signature Content-Disposition: inline -----BEGIN PGP SIGNATURE----- Version: GnuPG v2.0.9 (GNU/Linux) iD8DBQFJxOI6KGqCc1vIvggRAmGcAJsFUCYZIUGW9UOHzrky3j2ASlwZugCeLJI0 UJ+jS8xqwJBiBWE2uWjfw+w= =0N5y -----END PGP SIGNATURE----- --6c2NcOVqGQ03X4Wi--