Date: Sat, 24 May 2014 12:32:04 -0400 From: Tom Rhodes <trhodes@FreeBSD.org> To: Allan Jude <allanjude@freebsd.org> Cc: freebsd-doc@FreeBSD.org Subject: Re: docs/188214: Manpage for fsck(8) doesn't say what happens when no -t or -T Message-ID: <20140524123204.43dfca83.trhodes@FreeBSD.org> In-Reply-To: <201405231540.s4NFe0ZO096321@freefall.freebsd.org> References: <201405231540.s4NFe0ZO096321@freefall.freebsd.org>
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On Fri, 23 May 2014 15:40:00 GMT Allan Jude <allanjude@freebsd.org> wrote: > The following reply was made to PR docs/188214; it has been noted by GNATS. > > From: Allan Jude <allanjude@freebsd.org> > To: bug-followup@FreeBSD.org, rfg@tristatelogic.com, > Tom Rhodes <trhodes@FreeBSD.org> > Cc: > Subject: Re: docs/188214: Manpage for fsck(8) doesn't say what happens > when no -t or -T > Date: Fri, 23 May 2014 11:39:24 -0400 > > I have not checked the code to be sure, but from general usage I have > noticed that fsck(8) doesn't actually try to detect, or 'taste' the > partition, but only looks at /etc/fstab and if the type is not > specified, then returns the error. > > Suggesting that it 'attempts to detect' may give the wrong impression. > Someone would have to look at the source of fsck(8) to be sure. > So, in theory, an attempt to parse /etc/fstab would be an attempt to detect the type; however, my quick glance at the code showed no real parsing of fstab. But in my case, I followed to both the T and t flags, and just glanced at what was done would they not be specified. That was really as far as I got, and I attempted to use very generic language in case it only does one, or the other, or both. :) Reasonable? -- Tom Rhodes
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