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Date:      Wed, 20 Apr 2011 17:19:51 +0200
From:      Bastien Semene <bsemene@cyanide-studio.com>
To:        freebsd-questions@freebsd.org
Subject:   Re: redirecting command output depending on exit status
Message-ID:  <4DAEF997.6070400@cyanide-studio.com>
In-Reply-To: <20110420130106.GA30295@ei.bzerk.org>
References:  <4DAD9594.8030108@cyanide-studio.com> <20110420130106.GA30295@ei.bzerk.org>

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Bastien Semene
Administrateur Réseau&  Système

Cyanide Studio - FRANCE


Le 20/04/2011 15:01, Ruben de Groot a écrit :
> On Tue, Apr 19, 2011 at 04:00:52PM +0200, Bastien Semene typed:
>> Hi list,
>>
>> I have a cron task set up using lockf.
>>
>> I'd like to redirect one exit status to /dev/null :
>>
>> "it (lockf command) returns one of the exit codes defined in
>>       sysexits(3), as follows:
>>
>>       EX_TEMPFAIL   The specified lock file was already locked by another
>>                     process.
>>
>>       EX_CANTCREAT  The lockf utility was unable to create the lock
>> file, e.g.,
>>                     because of insufficient access privileges.
>>
>>       EX_USAGE      There was an error on the lockf command line.
>>
>>       EX_OSERR      A system call (e.g., fork(2)) failed unexpectedly.
>>
>>       EX_SOFTWARE   The command did not exit normally, but may have been
>> sig-
>>                     naled or stopped."
>>
>> I don't care about the EX_TEMPFAIL output as I consider it as a
>> successful exit status, not an error.
>>
>> I there a trick to do that in a short way ?
> something like
>
> logfile=/var/log/lockf.log
> lockf lockfile command
> [ $? -eq 75 ]&&  logfile=/dev/null ## EX_TEMPFAIL is defined to be 75
>
> Ruben
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I used this $? test in a script.
My question was to know if it is possible to do this in 1 command line, 
but I found nothing anywhere to do this.

Thank you for the answer !



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