From owner-freebsd-chat Wed Oct 15 22:06:34 1997 Return-Path: Received: (from root@localhost) by hub.freebsd.org (8.8.7/8.8.7) id WAA04754 for chat-outgoing; Wed, 15 Oct 1997 22:06:34 -0700 (PDT) (envelope-from owner-freebsd-chat) Received: from freebie.lemis.com (gregl1.lnk.telstra.net [139.130.136.133]) by hub.freebsd.org (8.8.7/8.8.7) with ESMTP id WAA04737 for ; Wed, 15 Oct 1997 22:06:28 -0700 (PDT) (envelope-from grog@freebie.lemis.com) Received: (from grog@localhost) by freebie.lemis.com (8.8.7/8.8.5) id OAA24576; Thu, 16 Oct 1997 14:35:29 +0930 (CST) Message-ID: <19971016143529.60886@lemis.com> Date: Thu, 16 Oct 1997 14:35:29 +0930 From: Greg Lehey To: "Jordan K. Hubbard" Cc: Ian Struble , chat@FreeBSD.ORG, Andreas Klemm , jkb , Jonathan Lemon Subject: Re: Linux vs. the rest of the world, poor OS comparison on web p References: <22771.876976931@time.cdrom.com> Mime-Version: 1.0 Content-Type: text/plain; charset=us-ascii X-Mailer: Mutt 0.84e In-Reply-To: <22771.876976931@time.cdrom.com>; from Jordan K. Hubbard on Wed, Oct 15, 1997 at 09:42:11PM -0700 Organisation: LEMIS, PO Box 460, Echunga SA 5153, Australia Phone: +61-8-8388-8250 Fax: +61-8-8388-8250 Mobile: +61-41-739-7062 WWW-Home-Page: http://www.lemis.com/~grog Fight-Spam-Now: http://www.cauce.org Sender: owner-freebsd-chat@FreeBSD.ORG X-Loop: FreeBSD.org Precedence: bulk On Wed, Oct 15, 1997 at 09:42:11PM -0700, Jordan K. Hubbard wrote: >> In the Oct 13 NetworkWorld on pg 21, there is a figure of 3-10 million linux >> users worldwide, so this 6 million figure may be a reasonable number. There > > Hmph. "We have approximately 3 million users, possibly even as many > as 10 million, so I guess we'll set a reasonable estimate at 6 > million." > > Say what? Am I the only one who's twigged to the number game going on > here? :-) I don't think you can be that sure about the upper and lower limits. I'd say there must be at least 25,000, because we've counted them. But are you sure that there are no more than 10,000,000? How can you be sure? I'd say it's possible that there are 20,000,000. Of course, I can't be sure about that, either. Let's split the difference (20,000,000 + 25,000)/2 = 10,000,000 within the limits of measurement error :-) Greg