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Date: Fri, 13 Jul 2001 14:50:48 -0400 (EDT)
From: Joe Clarke <marcus@marcuscom.com>
To: Graham White <graham@bravenet.com>
Cc: FreeBSD-questions <FreeBSD-questions@FreeBSD.ORG>
Subject: Re: Newbie Bash-question
In-Reply-To: <CIEEIPPHEMBKLIMPEJFBCEAOCBAA.graham@bravenet.com>
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[ expects an integer for both arg 1 and arg 2.  .30 is not an integer.

if [ $LOAD -qt 1 ]; then

should work for you.  IF you need more granularity, you can use Perl.

Joe Clarke

On Fri, 13 Jul 2001, Graham White wrote:

> I'm very new to scripting so bear with me. I'm trying to generate an e-mail
> when a load
> average on a server exceeds a certain point.  I can extract out the
> appropriate field with the command sequence below. I am however getting an
> integer expected error for the $LOAD
> variable.  I guess its pulling out the field as a string. Is there any way
> to convert it to an integer? Also is there an issue with the numbers being
> decimal? I hope this makes sense, thanks.
>
>
>
> LOAD=`uptime | sed -e "s/.*load average: \(.*\...\), .*\..., .*\.../\1/" -e
> "s/ //g"| cut -d"," -f5`
>
> if [ $LOAD -gt .30 ] #integer expected here.
>
>
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