Date: 02 Dec 2001 15:01:11 -0800 From: swear@blarg.net (Gary W. Swearingen) To: cjclark@alum.mit.edu Cc: Darren Pilgrim <dmp@pantherdragon.org>, freebsd-questions@FreeBSD.ORG Subject: Re: Changing $IFS in a bash shell Message-ID: <6tg06tp6q0.06t@localhost.localdomain> In-Reply-To: <20011201215816.P13613@blossom.cjclark.org> References: <3C097584.B51ECEBC@pantherdragon.org> <20011201173255.N13613@blossom.cjclark.org> <ausnaup7da.nau@localhost.localdomain> <20011201215816.P13613@blossom.cjclark.org>
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"Crist J . Clark" <cristjc@earthlink.net> writes:
> > 3) In ksh shell, this works: IFS="\n"
>
> But it doesn't work in bash.
So I thought I would give another one-liner that does, but I see
that bash, sh and ksh all strip trailing newlines with things like:
XXX=$(printf '\n')
XXX=`echo`
Except that ksh (only) will leave in a newline with:
XXX=$(printf '\\n')
Tested with:
echo -n "$XXX" | hd
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