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Cc: freebsd-questions@freebsd.org
Subject: Re: * wildcard in.sh script
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This is the output. want to build list only containing
file names prefixed with job. Putting " " around the value on the 
command line worked. But before this can go to production will have to 
fix the code so no " " on the command value.

#  >admin  "job*"
prefix_name1 = job*
prefix_name2 = job
  if job* != job
  list all1 = pen2
pen1
job_3
job_2
job_1
cell_B
cell_A
loop  = pen2
pen1
job_3
job_2
job_1
cell_B
cell_A*
hard stop


This is the code. From the results above the "for" is not looping 
through the file name list.

   dir=/usr/local
   prefix_name1=$1
   prefix_name2=`echo -n "${prefix_name1}" | sed 's/*.*$//'`

   echo "prefix_name1 = ${prefix_name1}"
   echo "prefix_name2 = ${prefix_name2}"

   echo " if ${prefix_name1} != ${prefix_name2}"
   if [ "${prefix_name1}" != "${prefix_name2}" ]; then

     [ -d "${dir}/etc/jail/" ] && \
       cd "${dir}/etc/jail/" && list=`ls | xargs rcorder`
     echo " list all1 = ${list}"
     # know this worked because see it in the o/p

     for jail in "${list}"*; do
      echo "loop  = ${jail}"
      # this only shows first file name in the o/p
      # though the * on the for command would do globbing
     done
   fi
exerr "hard stop"