Date: Tue, 11 Sep 2007 23:24:57 +1000 From: Andrew Milton <akm@theinternet.com.au> To: Luigi Rizzo <rizzo@icir.org> Cc: current@freebsd.org Subject: Re: how to tell 64 vs 32 bit architecture ? Message-ID: <20070911132457.GY4840@camelot.theinternet.com.au> In-Reply-To: <20070911055227.F62214@xorpc.icir.org> References: <20070906111028.A83649@xorpc.icir.org> <20070906222647.GB2737@kobe.laptop> <20070907000950.A91211@xorpc.icir.org> <20070907115021.GA2718@kobe.laptop> <20070907050310.A94579@xorpc.icir.org> <54b90fdf0709070654h103316f3sa3d423f4ff75fee3@mail.gmail.com> <20070911051653.A62022@xorpc.icir.org> <20070911123556.GF53667@deviant.kiev.zoral.com.ua> <20070911124857.GW4840@camelot.theinternet.com.au> <20070911055227.F62214@xorpc.icir.org>
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+-------[ Luigi Rizzo ]---------------------- | On Tue, Sep 11, 2007 at 10:48:57PM +1000, Andrew Milton wrote: | > On Tue, Sep 11, 2007 at 05:16:53AM -0700, Luigi Rizzo wrote: | > > | > > gcc 3.4 on a 32bit machine complains because the second constant | > > is too large. | > | > Can I ask why the 64 bit constant isn't 0xd00de123deadbeef , which would make | > bits 0-31 the same for both architectures, which might simplify the problem. | | because i want to run with very strict compiler checks and implicit | truncation is always flagged as a Bad Thing(TM). But even if you don't do implicit truncation, filling in the 'new' bits with a constant rather than shifting and filling the bottom bits would give you more options, or a better class of options? -- Andrew Milton akm@theinternet.com.au
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