Date: Mon, 25 Sep 2006 07:20:27 GMT From: Ed Schouten <ed@fxq.nl> To: freebsd-standards@FreeBSD.org Subject: Re: standards/99926: [Patch] [sh(1)'s jobs] POSIX compliancy by adding -p switch Message-ID: <200609250720.k8P7KRf0067223@freefall.freebsd.org>
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The following reply was made to PR standards/99926; it has been noted by GNATS. From: Ed Schouten <ed@fxq.nl> To: Roman Bogorodskiy <novel@FreeBSD.org> Cc: bug-followup@FreeBSD.org, Maxim Konovalov <maxim@FreeBSD.org> Subject: Re: standards/99926: [Patch] [sh(1)'s jobs] POSIX compliancy by adding -p switch Date: Mon, 25 Sep 2006 09:15:03 +0200 --FhHtzeYSSYv4Pwk7 Content-Type: text/plain; charset=us-ascii Content-Disposition: inline Content-Transfer-Encoding: quoted-printable * Roman Bogorodskiy <novel@FreeBSD.org> wrote: > > * Roman Bogorodskiy <novel@FreeBSD.org> wrote: > > > IMHO, this patch is wrong. You just print the actual PID of the proce= ss, > > > not the PID of the group leader. > > >=20 > > > I have a simular patch, which however prints PID of the group obtained > > > with getpgid() for the appropriate process: > > >=20 > > > http://people.freebsd.org/~novel/patches/freebsd/src_bin_sh_jobs_p.di= ff > >=20 > > It prints the PID of the first process, which is the process group > > leader. >=20 > Hm, sorry, I missed that part of the patch. However I wasn't able to > find out if the PID of the first process in group is the process group > leader in the docs. Is there any difference between getpgrp() and first > PID of the group? No, process groups are identified by the process ID of the group leader. --=20 Ed Schouten <ed@fxq.nl> WWW: http://g-rave.nl/ --FhHtzeYSSYv4Pwk7 Content-Type: application/pgp-signature Content-Disposition: inline -----BEGIN PGP SIGNATURE----- Version: GnuPG v1.4.5 (FreeBSD) iD8DBQFFF4H252SDGA2eCwURAhN3AJ9ZkChu/MlZYqjaTynjbqbXgp/xNACfYWIX eW3S72rWkQdjynK9KcrhgAA= =iqPR -----END PGP SIGNATURE----- --FhHtzeYSSYv4Pwk7--
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