Date: Mon, 14 May 2007 23:10:37 +0200 From: =?ISO-8859-2?Q?Jaros=B3aw_Staniek?= <js@iidea.pl> To: Drew Sanford <lauasanf@wilderness.homeip.net> Cc: Drew <cotharyus@gmail.com>, freebsd-questions@freebsd.org Subject: Re: STABLE + KEXI 1.1.2 (koffice 1.6.2) + KDE 3.5.6 = no sql? Message-ID: <4648D04D.7000401@iidea.pl> In-Reply-To: <4648ADB3.4010002@wilderness.homeip.net> References: <46465334.6020504@iidea.pl> <46472046.8000705@wilderness.homeip.net> <715841970705140552v7d6c5b6fgbee98cf256ad05e@mail.gmail.com> <4648AD91.1000301@iidea.pl> <4648ADB3.4010002@wilderness.homeip.net>
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Drew Sanford said the following, On 2007-05-14 20:42: > Jaros=B3aw Staniek wrote: >> Drew said the following, On 2007-05-14 14:52: >>> As promised, I'm attaching a database I just threw together. It only = has >>> four entries, and one query, but clearly the query should list=20 >>> everything in >>> table1. >> >> SELECT * FROM table1 ORDER BY "key" >> ^^^^ >> >> A quick note: "key" is reservered word in sql and kexi cannot deal=20 >> with it yet properly by adding "" or by displayng appropriate warning.= >> >> Could you change the column name to something neutral and try again=20 >> and let me know? >> >=20 > Sorry. There's a new table called table11 in there with basically the=20 > same data. There is _still_ a column called "key" in table11 you have sent me. Remov= e the=20 column and our query should work. Also queries that do not use the column work with table11, e.g.: SELECT vacation, users, date, vacation, id FROM table11 ORDER BY id; --=20 regards / pozdrawiam, Jaroslaw Staniek Sponsored by OpenOffice Polska (http://www.openoffice.com.pl/en) to wor= k on Kexi & KOffice: http://www.kexi.pl/en, http://www.koffice.org KDE3 & KDE4 Libraries for MS Windows: http://kdelibs.com, http://www.kd= e.org
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