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Date:      Tue, 25 May 1999 16:07:20 -0600 (CST)
From:      Eduardo Viruena Silva <mrspock@esfm.ipn.mx>
To:        Kent Stewart <kstewart@3-cities.com>
Cc:        freebsd-questions@freebsd.org, Mark Ovens <marko@uk.radan.com>
Subject:   Re: replace in vi...
Message-ID:  <Pine.OSF.3.96.990525155900.2706E-100000@Gina.esfm.ipn.mx>
In-Reply-To: <374B0143.BA408940@3-cities.com>

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On Tue, 25 May 1999, Kent Stewart wrote:

> 
> 
> Kent Stewart wrote:
> > 
> > Eduardo Viruena Silva wrote:
> > >
> > > ehem...
> > >
> > > I'm using  "vi" and I would like to know how to replace
> > > character '\0xb4'  by  character '\'' in all my text.
> > > [I mean, character which has code: 0xb4 = 0264 = 148
> > > by apostrophe]
> 
> I forgot to tell you that a 148 is a 0x94 and not a 0xb4.
> 

ooops!
sorry... 

> > What I did was the following
> > 
> > .,$s/^V<alt>+180/'/<cr>
> > 
> > The control V allows you to enter a special character and holding the
> > <alt> key down and pressing 180, enters your 0xb4. If you have more
> > than one occurance on a line, you will need to add a "g" at the end
> > after then last "/". I'm not on my FreeBSD system and it matters which
> > <alt>key you use.
> > 

it works!
thank you!
Mark Ovens also answered me and he suggested: ^Xcc   where cc is the
hex code of the character.   
It is more suitable because my X terminal is pretty weird and cannot
understand what a "alt-xxx" code is.  Nevertheless it worked in the
FreeBSD console.

Thank you Kent!
Thank you Mark!


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