Date: Tue, 14 Mar 2000 16:35:20 +0200 From: "Indiana Jones" <orinoki@hotmail.com> To: <freebsd-questions@freebsd.org> Subject: Problems using Freebsd kernel for IP forwarding Message-ID: <20000314144624.6159.qmail@hotmail.com>
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Hi,
We use a freebsd machine as a simple router with forwarding turned =
on.
Can someone explain the following kernel behavior:
1. we do 'route add 10.9.109.16/28 192.168.1.1'
2. then someone forwards traffic to address 10.9.109.21 =
through
this machine which correctly use this routing entry.
3. we then do 'route add 10.9.109.16/29 192.168.1.2'
now, when forwarding traffic again to the same IP address =
(10.9.109.21) the forwarding is still being done
according to the less specific forwarding rule (1) and not to the =
best match (3) rule (according to CIDR policy).
If the two rules are added w/o traffic being forwarded in the middle =
(i.e. w/o step 2), then the behavior is correct.
This seems like a bug!?
Thanks
Orinoki.
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<DIV><FONT face=3D"Bookman Old Style" size=3D2>Hi,</FONT></DIV>
<DIV> </DIV>
<DIV><FONT face=3D"Bookman Old Style" size=3D2> We use =
a freebsd=20
machine as a simple router with forwarding turned on.</FONT></DIV>
<DIV><FONT face=3D"Bookman Old Style" size=3D2> Can =
someone=20
explain the following kernel behavior:</FONT></DIV>
<DIV> </DIV>
<DIV><FONT face=3D"Bookman Old Style" size=3D2> =
=20
1. we do 'route add 10.9.109.16/28 =
192.168.1.1'</FONT></DIV>
<DIV><FONT face=3D"Bookman Old Style"=20
size=3D2> 2. &n=
bsp; then=20
someone forwards traffic to address 10.9.109.21 through</FONT></DIV>
<DIV><FONT face=3D"Bookman Old Style"=20
size=3D2> &nbs=
p; this=20
machine which correctly use this routing entry.</FONT></DIV>
<DIV><FONT face=3D"Bookman Old Style" size=3D2> =
=20
3. we then do 'route add 10.9.109.16/29 192.168.1.<FONT=20
face=3D"Bookman Old Style" size=3D2>2'</FONT></FONT></DIV>
<DIV> </DIV>
<DIV><FONT face=3D"Bookman Old Style" size=3D2> now, =
when=20
forwarding traffic again to the same IP address (10.9.109.21) the =
forwarding is=20
still being done</FONT></DIV>
<DIV><FONT face=3D"Bookman Old Style" size=3D2> =
according to the=20
less specific forwarding rule (1) and not to the best match (3) rule =
(according=20
to CIDR policy).</FONT></DIV>
<DIV><FONT face=3D"Bookman Old Style" size=3D2> If the =
two rules=20
are added w/o traffic being forwarded in the middle (i.e. w/o step 2), =
then the=20
behavior is correct.</FONT></DIV>
<DIV><FONT face=3D"Bookman Old Style" size=3D2> This =
seems like a=20
bug!?</FONT></DIV>
<DIV> </DIV>
<DIV><FONT face=3D"Bookman Old Style" size=3D2>Thanks</FONT></DIV>
<DIV><FONT face=3D"Bookman Old Style" size=3D2> =
=20
=
Orinoki.</FONT></DIV>
<DIV> </DIV></BODY></HTML>
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