Date: Tue, 04 Nov 2003 01:38:13 +0100 From: Alex de Kruijff <freebsd@akruijff.dds.nl> To: Odhiambo Washington <wash@wananchi.com>, freebsd-questions@freebsd.org Subject: Re: How does FreeBSD calculate disk sizes Message-ID: <20031104003813.GB4037@dds.nl> In-Reply-To: <20031103090715.GC20234@ns2.wananchi.com> References: <20031103090715.GC20234@ns2.wananchi.com>
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On Mon, Nov 03, 2003 at 12:07:15PM +0300, Odhiambo Washington wrote: > > Hello users, > > I have a disk which is actually 72GB. 2GB has been used as swap while > the rest was given to /. > > Can someone explain to me what I could be missing here, because what > I am seeing isn't what I expect. Perhaps it's just right while I am > the dumb one. Why isn't the whole size reported? > > > sucks# uname -nmr > sucks.wananchi.com 5.1-RELEASE-p10 i386 > > sucks# df -h > Filesystem Size Used Avail Capacity Mounted on > /dev/da0s1a 64G 1.8G 57G 3% / > devfs 1.0K 1.0K 0B 100% /dev > > Some expert explanation would help clear my ignorance! The answers can be found in the FAQ. The source is: http://www.freebsd.org/doc/en_US.ISO8859-1/books/faq/disks.html#DISK-MORE-THAN-FULL 9.25. How is it possible for a partition to be more than 100% full? A portion of each UFS partition (8%, by default) is reserved for use by the operating system and the root user. df(1) does not count that space when calculating the Capacity column, so it can exceed 100%. Also, you'll notice that the Blocks column is always greater than the sum of the Used and Avail columns, usually by a factor of 8%. For more details, look up the -m option in tunefs(8). -- Alex Articles based on solutions that I use: http://www.kruijff.org/alex/index.php?dir=docs/FreeBSD/
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