Date: Sun, 9 Nov 1997 10:51:17 -0500 (EST) From: "David E. Cross" <dec@phoenix.its.rpi.edu> To: Joerg Wunsch <joerg_wunsch@uriah.heep.sax.de> Cc: freebsd-hackers@FreeBSD.ORG Subject: Re: Why doesn't /bin/echo use getopt? Message-ID: <Pine.BSF.3.96.971109104957.6497A-100000@phoenix.its.rpi.edu> In-Reply-To: <19971109115007.JB56482@uriah.heep.sax.de>
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On Sun, 9 Nov 1997, J Wunsch wrote: > As James Raynard wrote: > > > Because it's supposed to repeat its arguments instead of parse them? > > (with the exception of -n, of course). > > Tough question: how do you echo a "-n\n" then (without using > printf(1), of course)? The same way you rm(1) a file named -rf/? rm -- -rf/ for echo: echo -- -n\n That would work with getopt(3). -- David Cross ACS Consultant
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