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Date: Tue, 3 Dec 2002 11:33:46 +0100
From: Roman Neuhauser <neuhauser@bellavista.cz>
To: Paul Everlund <tdv94ped@cs.umu.se>
Cc: Malik =?iso-8859-2?Q?B=FClent?= <bmalik@ihlas.net.tr>,
	questions@freebsd.org
Subject: Re: is there a "replace command" ?
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	Malik =?iso-8859-2?Q?B=FClent?= <bmalik@ihlas.net.tr>,
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References: <Pine.GSO.4.44.0212031113070.19346-100000@kvist.cs.umu.se>
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# tdv94ped@cs.umu.se / 2002-12-03 11:13:39 +0100:
> On Tue, 3 Dec 2002, Malik Bülent wrote:
> > But my expression has "/" that is there is a "/" in a expression
> > What shall i do ?
> > my expression is "new: 11"  I want to change "new: 11"  with "new/11"
> >
> > thanks
> 
> # echo "new: 11" | sed s/new\:\ 11/new\\/11/

    you don't have to use slashes for the delimiters. see sed(1).

    roman@freepuppy ~ 1003:0 > echo "new: 11" | sed 's,: ,/,'
    new/11
    roman@freepuppy ~ 1004:0 > echo "new: 11" | sed 's:\: :/:'
    new/11
    roman@freepuppy ~ 1005:0 > echo "new: 11" | sed 's-: -/-'
    new/11

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