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Date:      Mon, 20 Nov 2000 18:12:48 +0200
From:      Alex Koshterek <havoc@lookanswer.com>
To:        Peter Pentchev <roam@orbitel.bg>
Cc:        Thomas Moestl <tmoestl@gmx.net>, freebsd-hackers@FreeBSD.ORG
Subject:   Re: Byte order?
Message-ID:  <00112018145502.47740@pro.lookanswer.com>
In-Reply-To: <20001120175839.B6292@ringworld.oblivion.bg>
References:  <00112017175200.47740@pro.lookanswer.com> <00112017513301.47740@pro.lookanswer.com> <20001120175839.B6292@ringworld.oblivion.bg>

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пн , 20 ноя 2000, Peter Pentchev написал:
> On Mon, Nov 20, 2000 at 05:47:47PM +0200, Alex Koshterek wrote:
> > > This program gets it wrong. When the last byte of a long is set after the long was
> > > set to 1, we have a big endian architecture (the "little" end is at the 4th byte,
> > > so the "big end" is at the 1st byte).
> > > The x86 architecture _is_ little endian.
> > > 
> > What? 
> > on x86  long a =1
> > in memory is a  01 00 00 00
> > Lesser significant byte is first and most significant is last
> 
> Exactly - the least significant byte comes first, the number is stored
> in memory from its 'little' end towards its 'big' end - hence, little-endian.
> 
Thanks. We all mean same thing, but I called it incorrectly   ;-)
I`m stupid
Sorry and thanks.


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