Date: Tue, 09 Apr 2002 01:20:23 +0200 From: Michael Nottebrock <michaelnottebrock@gmx.net> To: Peter Leftwich <Hostmaster@Video2Video.Com> Cc: FreeBSD Questions <FreeBSD-Questions@FreeBSD.ORG>, FreeBSD Ports <FreeBSD-Ports@FreeBSD.ORG> Subject: Re: gcc -O -mcpu=i686 -howtooverride=486? Message-ID: <3CB225B7.4090405@gmx.net> References: <20020408140315.J8518-100000@66-75-1-142.san.rr.com>
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Peter Leftwich wrote: > My question is the following-- It seems like my /etc/make.conf file (which > I think I either mv'ed or cp'ed from /usr/local/etc/make.conf) is getting > ignored as far as the "CPUTYPE=i686" flag goes. How do I remedy this? > > I have been editing the various "Makefile" files, overriding the usual "-O > -m486" with "-O -mcpu=i686" (what is -march by the way?) but my extended > question is the following-- Does the -mcpu flag that mean [paraphrase-ically] > "use i686 instructions for the compile process" or does it mean "compile > some binaries with i686 smartness built into them?" Know-whuht-eye-mean? CPUTYPE= sets -march, not mcpu. From the gcc documentation (i386-specific): ----snip -mcpu=cpu type Assume the defaults for the machine type cpu type when scheduling instructions. The choices for cpu type are: `i386' `i486' `i586' `i686' `pentium' `pentiumpro' `k6' While picking a specific cpu type will schedule things appropriately for that particular chip, the compiler will not generate any code that does not run on the i386 without the `-march=cpu type' option being used. `i586' is equivalent to `pentium' and `i686' is equivalent to `pentiumpro'. `k6' is the AMD chip as opposed to the Intel ones. -march=cpu type Generate instructions for the machine type cpu type. The choices for cpu type are the same as for `-mcpu'. Moreover, specifying `-march=cpu type' implies `-mcpu=cpu type' ----snip -- Michael Nottebrock To Unsubscribe: send mail to majordomo@FreeBSD.org with "unsubscribe freebsd-ports" in the body of the message
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