Date: Fri, 18 Jan 2013 23:45:37 +0000 From: Vincent Hoffman <vince@unsane.co.uk> To: Fbsd8 <fbsd8@a1poweruser.com> Cc: FreeBSD questions <questions@freebsd.org> Subject: Re: sh script code to get file size. Message-ID: <50F9DEA1.4000902@unsane.co.uk> In-Reply-To: <50F9DA3E.5050607@a1poweruser.com> References: <50F9DA3E.5050607@a1poweruser.com>
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On 18/01/2013 23:26, Fbsd8 wrote:
> In a script in am working on I need to find out the allocated
> size of a sparse file.
> The only command that comes to mind is "ls -lh"
> The "du -h" command is not appropriate because it will show
> the occupied size and not the allocated size.
>
> I don't know how to parse out to the position in the output of that
> "ls -lh" command to pickup the file size value.
>
> Is there some other way to do this?
cut or awk spring to mind. I'm sure there are more :)
(23:31:48 <~>) 0
jhary@ostracod $ ls -lh Cisco-vpn-Profiles.zip | cut -f 5 -w
16k
(23:32:15 <~>) 0
jhary@ostracod $ ls -lh Cisco-vpn-Profiles.zip | awk '{print $5}'
16k
(23:32:25 <~>) 0
jhary@ostracod $ ls -lh Cisco-vpn-Profiles.zip
-rw-r--r-- 1 jhary wheel 16k 11 Jul 2004 Cisco-vpn-Profiles.zip
(23:32:32 <~>) 0
jhary@ostracod $
Vince
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