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Date:      Tue, 23 Aug 2005 11:57:52 +0300
From:      Ruslan Ermilov <ru@freebsd.org>
To:        vladone <vladone@spaingsm.com>
Cc:        freebsd-ipfw@freebsd.org, freebsd-questions@freebsd.org
Subject:   Re: error when use table option with ipfw
Message-ID:  <20050823085752.GB15272@ip.net.ua>
In-Reply-To: <163971811.20050823111033@spaingsm.com>
References:  <163971811.20050823111033@spaingsm.com>

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On Tue, Aug 23, 2005 at 11:10:33AM +0300, vladone wrote:
> Hi!
> I try to use table option but not work.
> First, i use Freebsd 5.4 release.
> In short i have:
> cmd=3D"ipfw -q"
>=20
> $cmd table 1 add 192.168.0.0/24
> $cmd table 1 add 192.168.2.0/24
> $cmd table 1 add 192.168.3.0/24
> $cmd table 1 add 192.168.4.0/24
>=20
> $cmd add 700 count ip from table(1) to any via $lif
>=20
> When i run the script i receive an error about syntax error "ipfw.sh: 78:=
 Syntax error: "(" unexpected".
> I dont understand where is error?
> Need some compiler options to work with this option?
> If i give:
> #ipfw table 1 list
> i have list of entries in this table without any error.
>=20
Since this is a shell script, `(' has a special meaning to group
commands for executing them in a sub-shell.  To cancel a special
meaning, you can prefix it with the `\' character.


Cheers,
--=20
Ruslan Ermilov
ru@FreeBSD.org
FreeBSD committer

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