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Date: Thu, 05 Nov 2009 10:41:23 -0400
From: PJ <af.gourmet@videotron.ca>
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To: Ruben de Groot <mail25@bzerk.org>, PJ <af.gourmet@videotron.ca>,
	Polytropon <freebsd@edvax.de>,
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Cc: 
Subject: Re: and now for conky & gremlins
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Ruben de Groot wrote:
> On Thu, Nov 05, 2009 at 09:26:15AM -0400, PJ typed:
>   
>> Polytropon wrote:
>>     
>>> On Wed, 04 Nov 2009 18:25:58 -0400, PJ <af.gourmet@videotron.ca> wrote:
>>>   
>>>       
>>>> output should be: 1  2  3 [4] 5 6 7 etc.
>>>> is:    1 2 3 4 5 6....
>>>>
>>>> the calendar.sh is exactly:
>>>> #!/bin/sh
>>>> cal | awk 'NR>1' | sed -e 's/   /    /g' -e 's/[^ ] /& /g' -e 's/..*/ 
>>>> &/' -e "s/\ `date +%d`/\[`date +%d`\]/"
>>>>     
>>>>         
>>> It's quite obviously. Let's try the last substitution
>>> argument in plain shell:
>>>
>>> 	% date +%d
>>> 	05
>>>
>>> But the command creates this:
>>>
>>> 	 Su  Mo  Tu  We  Th  Fr  Sa
>>> 	  1   2   3   4   5   6   7
>>>
>>> The leading zero is missing, so there's no substition that
>>> changes "5" into "[5]", because the search pattern is "05".
>>>   
>>>       
>> Ok, I see... I'm not too good in programming. I guess I didn't notice
>> the previous to the first days of November the date was always 2
>> digits.. how do I get rid of the zero? Regex substitution or something
>> like that?
>>     
>
> date "+%e" should do it.
>   
Sure did....  For the moment, I changed the [ ] to just plain >
maybe that will avoid the disjointed row.
But changing the color of the current date sure would be nice... but is
there a way to do that?