Date: Sun, 28 Sep 1997 08:36:19 +0200 From: j@uriah.heep.sax.de (J Wunsch) To: hackers@FreeBSD.ORG Subject: Re: Timeout for sh(1) 'read' ?? Message-ID: <19970928083619.EN11505@uriah.heep.sax.de> In-Reply-To: <199709280603.PAA04849@word.smith.net.au>; from Mike Smith on Sep 28, 1997 15:33:13 %2B0930 References: <19970928073430.CC50911@uriah.heep.sax.de> <199709280603.PAA04849@word.smith.net.au>
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As Mike Smith wrote: > > $foo=${foo:-default} > > Hmm. Actually, you would get the desired behaviour with > > val=${default} Well, sure. I didn't see this. :) You need to assign a value in the first place anyway. > read -t 5 val > > because read won't have had a chance to modify 'val' if it does time > out. So should read return an error if it times out? What does ksh do? It does: j@uriah 66% ksh93 $ read -t 5 foo # and just wait $ echo $? 1 $ read -t 5 foo babble $ echo $? 0 $ exit -- cheers, J"org joerg_wunsch@uriah.heep.sax.de -- http://www.sax.de/~joerg/ -- NIC: JW11-RIPE Never trust an operating system you don't have sources for. ;-)
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