Date: Wed, 23 Sep 1998 18:38:50 +0200 (CEST) From: Andre Albsmeier <andre.albsmeier@mchp.siemens.de> To: dnelson@emsphone.com (Dan Nelson) Cc: andre.albsmeier@mchp.siemens.de, hamilton@pobox.com, freebsd-questions@FreeBSD.ORG Subject: Re: How to get the PID before a program is run? (No joke :-) Message-ID: <199809231638.SAA02576@internal> In-Reply-To: <19980923111119.A2733@emsphone.com> from Dan Nelson at "Sep 23, 98 11:11:19 am"
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> In the last episode (Sep 23), Andre Albsmeier said: > > someone wrote: > > > In message <199809230729.JAA12131@internal>, Andre Albsmeier wrote: > > > } I want to start a program but I need its PID before it is run. > > > } One way would be to load the program and send a -STOP signal very > > > } quickly. Then I have got the PID, can do some things and send a > > > } -CONT signal when finished. > > > > > > It's actually fairly simple, though somewhat off the beaten path. > > > Something like: > > > > > > #!/bin/sh > > > echo "PID is $$" > > > exec /your/program/here > > > > OK, this replaces my shell script. But I have to do some stuff later > > when /your/program/here is finished. > > Well, you could call that script from _another_ script :) You should > be able to do this in one shell script, like this: > > #! /bin/sh > ( > echo $$ > /var/run/prog.pid > echo 'program starting with pid $$' > exec /bin/prog > ) > echo 'program finished' > > ,but according to the sh manpage, subshells keep $$ at the original > shell's pid, so $$ in the above script has the wrong pid. You'll have > to split it into two scripts. Yes, the thing with the two scripts appears to be the only way. Thanks a lot, -Andre To Unsubscribe: send mail to majordomo@FreeBSD.org with "unsubscribe freebsd-questions" in the body of the message
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