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Date:      Thu, 5 Sep 2002 15:51:15 +0100
From:      Ceri Davies <setantae@submonkey.net>
To:        Roman Neuhauser <neuhauser@bellavista.cz>
Cc:        freebsd-questions@freebsd.org
Subject:   Re: mount(8) mount_union(8) and the slippery wet floor...
Message-ID:  <20020905145115.GA14407@submonkey.net>
In-Reply-To: <20020905144627.GL10717@freepuppy.bellavista.cz>
References:  <5.1.0.14.0.20020904132723.00bc28e8@mail.lusidor.nu> <20020904124832.GA15994@submonkey.net> <44y9ahecn2.fsf@be-well.ilk.org> <20020905091754.GE10717@freepuppy.bellavista.cz> <44bs7c1phq.fsf@be-well.ilk.org> <20020905144627.GL10717@freepuppy.bellavista.cz>

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On Thu, Sep 05, 2002 at 04:46:28PM +0200, Roman Neuhauser wrote:
> 
>     this is interesting. I always thought that mount(8) works by
>     invoking mount_whatever(8) where whatever is determined by the value
>     passed in the -t option to mount(8). looks like this isn't the case,
>     then... hm: 

No, that is the case, but this is what confused me.

>       If the type is not one of the internally known types, mount will
>       attempt to execute a program in /sbin/mount_XXX where XXX is
>       replaced by the type name.  For example, nfs filesystems are
>       mounted by the program /sbin/mount_nfs.

That works if you run "mount -t union ...", but after rereading the OP's
question, he was referring to "mount -o union..." which is something
different.

Ceri

-- 
you can't see when light's so strong
you can't see when light is gone

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