Date: Fri, 26 Jan 2001 00:34:43 -0800 (Pacific Standard Time) From: Joseph Stein <joes@joescanner.com> To: <questions@freebsd.org> Subject: Formatting a number Message-ID: <Pine.WNT.4.31.0101260023520.728-100000@hood>
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I am beating my head up trying to figure out how to do this; I've tried
(what little I know) Perl, sed, awk, etc, and am stumped. This is my
last-ditch resort...
I have a script that checks the size of a staging directory (for
offloading data to CD-R). It does a rudimentary check with something like
this:
DIRSIZE=`du -k /var/backup | tail -1 | awk '{ print $1 }'`
That works just fine, and gives me the number of kilobytes used by my
staging directory.
However, because I am a want to see real numbers, I also pass it through a
short perl script as well, for the report that gets mailed to me:
perl -e "printf('is %10d bytes (%dK, %dM). (%5.2f%%)',\
${DIRSIZE}*1024, ${DIRSIZE}, ${DIRSIZE}/1024, ((${DIRSIZE}/716800)*100));"\
>>/tmp/tempfile.$$.1
This outputs something like...
is 470768640 bytes (459735K, 448M). (65.68%)
But, I want that first really big number (ok, the second one too) to be
formatted a la
470,768,640 bytes (459,735K; 448M). (65.68%)
Any ideas? I know this is possible (but I haven't done it since my "Intro
to Unix course years ago, and forgot how).
Thanks in advance for any help,
joe
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