Skip site navigation (1)Skip section navigation (2)
Date:      Wed, 24 Aug 2005 04:56:34 +1000
From:      Peter Jeremy <PeterJeremy@optushome.com.au>
To:        Borja Marcos <borjamar@sarenet.es>
Cc:        freebsd-hackers@freebsd.org
Subject:   Re: IBM Active Protection System Approach
Message-ID:  <20050823185634.GE37107@cirb503493.alcatel.com.au>
In-Reply-To: <34E57F6C-EDF8-4E51-86AC-863109217B85@sarenet.es>
References:  <200508221720.j7MHKpNb022773@peedub.jennejohn.org> <430B11B0.20702@pacific.net.sg> <200508232155.02444.doconnor@gsoft.com.au> <34E57F6C-EDF8-4E51-86AC-863109217B85@sarenet.es>

next in thread | previous in thread | raw e-mail | index | archive | help
On Tue, 2005-Aug-23 15:37:49 +0200, Borja Marcos wrote:
>>mmm.. There is a static 1G force on the laptop while it is on your  
>>desk. When
>>it falls it goes to 0G as it is in free fall.
>>
>>Still.. "delta G == park laptop heads" :)
>
>    It's not a "force meter", but an acelerometer. It measures  
>acceleration. If the computer is sitting on your desk, as it has  
>already been said, it detects nothing. When falling, the acceleration  
>is 1 G, ie, 9.8 m/s^2

Actually, it's the other way round.  The accelerometer is detecting
acceleration within the frame of reference of your laptop.  When
sitting on your desk (or holding it stationary in your hand), the
accelerometer will detect a static 1G acceleration.  Whilst your
laptop is falling, the accelerometer reads 0G (neglecting air
friction) because your whole laptop is accelerating.

It might be easier to think of the accelerometer measuring the force
exerted by a fixed mass sitting on your laptop.

-- 
Peter Jeremy



Want to link to this message? Use this URL: <https://mail-archive.FreeBSD.org/cgi/mid.cgi?20050823185634.GE37107>