Date: Mon, 20 Oct 1997 17:43:13 -0700 (PDT) From: Donald Burr <dburr@POBoxes.com> To: questions@FreeBSD.ORG Cc: jabbott@blue.pca.state.mn.us Subject: RE: questions-digest V3 #489 Message-ID: <XFMail.971020174533.dburr@POBoxes.com> In-Reply-To: <199710202356.QAA29920@hub.freebsd.org>
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My secret spy satellite informs me that on 20-Oct-97,
owner-questions-digest@FreeBSD.ORG wrote:
>From: abbott on blue <jabbott@blue.pca.state.mn.us>
>Date: Mon, 20 Oct 1997 10:13:24 -0500
>Subject: Unix question. Regular expressions in commands?
>
>I guess this is kind of a newbie unix question. I have just learned
>about
>regular expressions within perl and so am trying to use them everyplace.
>:-)
>
>>From a command line what I would like to do is....
># mv *.[dump asc dat txt clean] tablecreation
There are differences (some subtle, some not) between Perl-ish regexps and
regexps used by other unix programs (e.g. shell).
In shell-ese, what you want to do should be stated as:
# mv *.{dump,asc,dat,txt,clean} tablecreation
Note the usage of {} instead of [], and the arguments are separated by
commas, not spaces.
Read the regexp(3) man page to for more information on how the rest of the
unix world handles regexps.
- ---
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