Date: Mon, 18 Dec 2000 03:53:19 From: "Aaron Hill" <hillaa@hotmail.com> To: questions@freebsd.org Subject: Script: Variable substition within a variable? Message-ID: <F175g2UVe3lQN5vnoqt00000f22@hotmail.com>
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Hello! Can anyone help with a script problem I'm having. Please let me explain what I'm trying to do with two example files... fileone: $name filetwo: #!/bin/sh name="Aaron" fileone=`cat fileone` echo "Your name is $fileone" When you execute filetwo this is the output you get: Your name is $name The output I would like to get is: Your name is Aaron Can anyone point out if I've missed something fundamental or if there's something that could help me do this substition. Thanks Aaron Hill _________________________________________________________________________ Get Your Private, Free E-mail from MSN Hotmail at http://www.hotmail.com. To Unsubscribe: send mail to majordomo@FreeBSD.org with "unsubscribe freebsd-questions" in the body of the message
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