Date: Mon, 14 Feb 2011 23:54:06 +0100 From: Roland Smith <rsmith@xs4all.nl> To: "Jack L. Stone" <jacks@sage-american.com> Cc: freebsd-questions@freebsd.org Subject: Re: script help Message-ID: <20110214225406.GA69832@slackbox.erewhon.net> In-Reply-To: <3.0.1.32.20110214163437.019167e0@sage-american.com> References: <3.0.1.32.20110214163437.019167e0@sage-american.com>
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On Mon, Feb 14, 2011 at 04:34:37PM -0600, Jack L. Stone wrote:
> # find all of the same filenames (copyright.htm) and then replace the year
> 2010 with 2011 in each file. Once I have a working script, I should be ab=
le
> to add it as a cron job to run on the first day of each new year.
The following command should do the trick, I think.
find / -type f -name copyright.htm -exec sed -i .bak -e 's/Copyright =A9 20=
=2E./Copyright =A9 2011/g' {} \;
Basically the find(1) command locates the files you want to change, and than
for every file it calls sed(1) with the -i flag to do the in-place
editing. The originals are saved as copyright.htm.bak. If all goes well, you
can delete those.
Depending on the contents of the files, you might want to just replace 2010=
by
2011, or use a little more context as I did in the example, to make sure on=
ly
the right numbers are replaced.
Roland
--=20
R.F.Smith http://www.xs4all.nl/~rsmith/
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