Date: Tue, 11 Dec 2007 22:22:17 +0100 From: Tino Engel <elrap@web.de> To: Halid Faith <maslak@ihlas.net.tr> Cc: freebsd-questions@freebsd.org Subject: Re: How to replace two strings in a file in the same time with sed command ? Message-ID: <475EFF89.9040406@web.de> In-Reply-To: <001001c83c33$669b46b0$dc96eed5@ihlasnetym> References: <002801c83c11$cd434e70$dc96eed5@ihlasnetym> <475EC318.90104@dial.pipex.com> <001001c83c33$669b46b0$dc96eed5@ihlasnetym>
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Halid Faith schrieb:
> Ok
> But I have another problem,
> I couldn't use any command interior of sed command. That's to say I have a
> script;
>
> yy="file5"
> for i in `cat file1`;
> do
> sed -e 's/old1/new1\ \'$i'/g' -e 's/old2/'cut -d, -f 1 ${yy}'/g' file2 >
> file3
> done
>
> When I run the script, I get an error, due to using cut command
>
>
>
>
For using environment variables in sed, you have to use # instead of /
VAR="TEXT"
sed s#OLD#${VAR}#g file1
Will replace OLD by TEXT. Do not use quotations here...
Rg, Tino
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