Date: Mon, 5 Jul 2010 06:33:22 +0530 From: Subhro Kar <subhro.kar@gmail.com> To: Thomas Keusch <fwd@bsd-solutions-duesseldorf.de>, Luca Renaud <renaud.luca@gmail.com> Cc: freebsd-questions@freebsd.org Subject: Re: Get access to csh (default freebsd shell) for root to solve login problem. Message-ID: <32828DBC-024F-4B50-ACBA-54FDEC298393@gmail.com> In-Reply-To: <20100704161806.GA10779@gothschlampen.com> References: <AANLkTimr2ikyYisgMqJ6jyYmlkQgtsq3l53gRHaZVF8i@mail.gmail.com> <20100704161806.GA10779@gothschlampen.com>
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On 04-Jul-2010, at 9:48 PM, Thomas Keusch wrote:
> On Sun, Jul 04, 2010 at 05:02:59PM +0100, Luca Renaud wrote:
>=20
> Hi,
>=20
>> The root shell is now bash,but I was unaware that bash was not
>> self-contained(it depends at least of libintl.so.8),
>> and doing some upgrades with ports I erased libintl.so.8,now I cannot =
access
>> the root account because bash is
>> not operational and I need root access to install again =
libintl.so.8,or any
>> other way to solve the problem.
>> So,how can I get access to csh for root without having access to a =
root
>> shell(the previously defined bash does
>> not work,and I need root access to change the shell for the root =
acount).
>=20
> if you haven't activated the 'toor' account (another UID 0 account =
besides
> root), you'll have to boot from fixit media (or another live cd / =
system) and
> go from there.
I think that would be an overkill. =46rom the su(1) manpage,=20
-m Leave the environment unmodified. The invoked shell is =
your
login shell, and no directory changes are made. As a =
security
precaution, if the target user's shell is a non-standard =
shell
(as defined by getusershell(3)) and the caller's real uid =
is non-
zero, su will fail.
So, you could use su -m to switch to root and remain in the same shell =
as your user calling su. Once there, AFAIK, you could use vipw(8) or =
chsh(1) to change the root shell back to csh.
Thanks
Subhro
--
Subhro Kar
Blog: http://80386.org
Twitter: http://twitter.com/subhrokar
FaceBook: http://www.facebook.com/subhrokar=
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