Date: Tue, 23 Aug 2005 11:10:33 +0300 From: vladone <vladone@spaingsm.com> To: freebsd-questions@freebsd.org Cc: freebsd-ipfw@freebsd.org Subject: error when use table option with ipfw Message-ID: <163971811.20050823111033@spaingsm.com>
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Hi!
I try to use table option but not work.
First, i use Freebsd 5.4 release.
In short i have:
cmd="ipfw -q"
$cmd table 1 add 192.168.0.0/24
$cmd table 1 add 192.168.2.0/24
$cmd table 1 add 192.168.3.0/24
$cmd table 1 add 192.168.4.0/24
$cmd add 700 count ip from table(1) to any via $lif
When i run the script i receive an error about syntax error "ipfw.sh: 78: Syntax error: "(" unexpected".
I dont understand where is error?
Need some compiler options to work with this option?
If i give:
#ipfw table 1 list
i have list of entries in this table without any error.
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