Date: Tue, 23 Aug 2005 11:17:38 +0300 From: Jara <hugle@vkt.lt> To: freebsd-questions@freebsd.org Subject: Re: error when use table option with ipfw Message-ID: <663380839.20050823111738@vkt.lt> In-Reply-To: <163971811.20050823111033@spaingsm.com> References: <163971811.20050823111033@spaingsm.com>
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$cmd add 700 count ip from table'(1)' to any via $lif
Jarek
---------------------------------------
> Hi!
> I try to use table option but not work.
> First, i use Freebsd 5.4 release.
> In short i have:
> cmd="ipfw -q"
> $cmd table 1 add 192.168.0.0/24
> $cmd table 1 add 192.168.2.0/24
> $cmd table 1 add 192.168.3.0/24
> $cmd table 1 add 192.168.4.0/24
> $cmd add 700 count ip from table(1) to any via $lif
> When i run the script i receive an error about syntax error
> "ipfw.sh: 78: Syntax error: "(" unexpected".
> I dont understand where is error?
> Need some compiler options to work with this option?
> If i give:
> #ipfw table 1 list
> i have list of entries in this table without any error.
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