Skip site navigation (1)Skip section navigation (2)
Date:      Tue, 9 Oct 2001 14:49:00 +1000 
From:      "Pietralla, Siegfried P" <siegfried.pietralla@eds.com>
To:        "'BSD Freak'" <bsd-freak@mbox.com.au>, FreeBSD Questions <freebsd-questions@FreeBSD.ORG>
Subject:   RE: Outputing a specific line number to standard output
Message-ID:  <16649A8D5C73D51183B80008C728EEB7CC09E6@AUSYM103>

next in thread | raw e-mail | index | archive | help
hi there,

two simple ways:

using awk:

$ awk 'NR==54{print;exit}' myfile.txt

using head and tail:

$ tail +54 myfile.txt | head -1

regards,
siegfried.

-----Original Message-----
From: BSD Freak [mailto:bsd-freak@mbox.com.au]
Sent: Tuesday, 9 October 2001 14:30
To: FreeBSD Questions
Subject: Outputing a specific line number to standard output


Hi all,

I feel stupid asking this but I have looked in the man page for grep,
sort , cat, head and cut and have not been able to find the answer. 

How do I output to standard output a particular line number in a text file? 

For example say I want to display line 54 in the file myfile.txt . How
do I do this?


Thanks in advance.....

---------------------------------------------------------------------
mBox is unified messaging and now has the mBeeper!
Be the first to trial it.
http://www.mbox.com.au/mbeeper

To Unsubscribe: send mail to majordomo@FreeBSD.org
with "unsubscribe freebsd-questions" in the body of the message

To Unsubscribe: send mail to majordomo@FreeBSD.org
with "unsubscribe freebsd-questions" in the body of the message




Want to link to this message? Use this URL: <https://mail-archive.FreeBSD.org/cgi/mid.cgi?16649A8D5C73D51183B80008C728EEB7CC09E6>